SME
Oceanography · Problem type

Wave energy and power

Use this for “Waves 2 m high arrive every 10 s. How much energy does each square meter of sea hold, and how much power reaches each meter of coast?”

Diagram

L = 156.1 ma = 1 mheights not to scale
Crest to crest is one wavelength, 156.1 m.
The crest rises 1 m above the middle.
This is an example. Type your own values to start a new problem.
E (J/m²)
=
ρ
×
g
×
(
H (m)
)
2
÷
8
P (kW/m)
=
E (J/m²)
×
cg (m/s)
H is the wave height, crest to trough, twice the amplitude the picture marks; P is the power each meter of crest carries.
T
Period
example · s

Formulas

E
=
1,025
×
9.81
×
H
2
8
5,027.625
=
1,025
×
9.81
×
2
2
8
cg
=
9.81
×
T
4 × π
7.8065
=
9.81
×
10
4 × π
P
=
E
×
cg
1,000
39.2484
=
5,027.625
×
7.8065
1,000

Assumptions

•
Deep-water waves of one height and period; seawater is 1,025 kg/m³ and g = 9.81 m/s².
•
The energy, half in the moving water and half in the raised surface, is E = ρgH² ÷ 8 per m² of sea.
•
It travels at the group speed cg = gT ÷ 4π, half the wave speed.

Step-by-step

WE KNOW
H = 2 m, T = 10 s
FIND
wave energy (E), group speed (cg), wave power along the crest (P)
Step 1 · Find wave energy (E)
Use E = 1,025 × 9.81 × H² ÷ 8
The energy grows with the square of the height: twice as high holds four times as much.
E
=
1,025
×
9.81
×
2
2
8
E
=
1,025
×
9.81
×
4
8
E
=
10,055.25
×
4
8
E
=
40,221
8
E
=
5,027.625
J/
m
2
Step 2 · Find group speed (cg)
Use cg = 9.81 × T ÷ (4 × π)
In
deep
water
the
energy
moves
at
half
the
wave
speed
gT
2π
.
cg
=
9.81
×
10
4 × π
cg
=
98.1
4π
cg = 7.80655 m/s
Step 3 · Find wave power along the crest (P)
Use P = E × cg ÷ 1,000
The
energy
per
m
2
carried
along
at
the
group
speed,
in
watts,
then
watts
to
kilowatts.
P
=
5,027.625
×
7.80655
1,000
P
=
39,250
1,000
P
=
39.2484
kW/m
Check
Put the numbers back in. Both sides should match.
5,027.625
=
1,025
×
9.81
×
2
2
8
✓
7.80655
=
9.81
×
10
4 × π
✓
39.2484
=
5,027.625
×
7.80655
1,000
✓
Topic check
See what you know: 5 questions on this topic
New questions each time. Pass to mark it complete.

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