SME
Manufacturing Processes · Problem type
Taylor tool life
Use this for “A carbide tool has n = 0.25 and C = 400 m/min. How long does it last cutting at 200 m/min?”
Chart
v(T) = 400T−0.25
Log–log axes: a power law draws as a straight line.
This is an example. Type your own values to start a new problem.
v (m/min)
×
(
T (min)
)
=
C (m/min)
Formulas
v
×
T
n
=
C
200
×
16
0.25
=
400
Assumptions
•
vTⁿ = C holds for one tool, work material, feed and depth; n and C come from wear tests.
•
T is the cutting time until the tool reaches its wear limit; C is the speed for 1 min of life.
•
With n = 0.25, doubling v divides the life by 2⁴ = 16.
Step-by-step
WE KNOW
v = 200 m/min, n = 0.25, C = 400 m/min
FIND
tool life (T)
Step 1 · Find tool life (T)
Use v × Tⁿ = C
Divide
both
sides
by
v
,
then
undo
the
power
n
by
raising
to
1
n
.
T
=
(
C
v
)
1 ÷
n
T
=
(
400
200
)
1 ÷ 0.25
T
=
2
4
T
=
16
min
Check
Put the numbers back in. Both sides should match.
200
×
16
0.25
=
400
✓
Topic check
See what you know: 5 questions on this topic
New questions each time. Pass to mark it complete.
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