Separation Processes · Problem type

Rectifying operating line

Use this for “A column runs at reflux ratio 3 with a 90% distillate. What are the slope and intercept of the top operating line?”

Diagram

00.20.40.60.8100.20.40.60.81x (liquid mole fraction of A)y (vapor)xD ÷ (R + 1) = 0.3slope 0.6842xDEquilibrium, α = 2.5Operating
Equilibrium
curve:
y
=
αx
1 + (α − 1)x
with
α
=
2.5;
the
45°
line
is
y
=
x.
Rectifying
line:
y
=
(
R
R + 1
)x
+
xD
R + 1
=
0.684x
+
0.3,
through
(xD,
xD).
This is an example. Type your own values to start a new problem.
m
=
R
+
1
b
=
xD
+
1

Formulas

m
=
R
R
+ 1
0.6842
=
2.167
2.167 + 1
b
=
xD
R
+ 1
0.3
=
0.95
2.167 + 1

Assumptions

•
Constant molar overflow above the feed: L and V do not change from stage to stage.
•
Total condenser, so the reflux has the distillate’s composition xD.
•
The curve is drawn for α = 2.5 only to show where the line sits.

Step-by-step

WE KNOW
R = 2.167, xD = 0.95
FIND
slope (m), intercept on y (b)
Step 1 · Find slope (m)
Use m = R ÷ (R + 1)
Above
the
feed
L
V
=
R
R
+ 1
:
the
liquid
coming
down
over
the
vapor
going
up.
m
=
2.167
2.167 + 1
m
=
2.167
3.167
m
=
0.6842
Step 2 · Find intercept on y (b)
Use b = xD ÷ (R + 1)
The line through (xD, xD) with that slope meets x = 0 here.
b
=
0.95
2.167 + 1
b
=
0.95
3.167
b
=
0.3
Check
Put the numbers back in. Both sides should match.
0.6842
=
2.167
2.167 + 1
✓
0.3
=
0.95
2.167 + 1
✓
Topic check
See what you know: 5 questions on this topic
New questions each time. Pass to mark it complete.

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