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Grade 10 Math · Geometry

Coordinate geometry: distance, midpoint, partitioning a segment and coordinate proofs

Use this for “Find the distance between (−3, 2) and (5, 8).”

Chart

−10−10−8−8−6−6−4−4−2−2224466881010xy8 across6 upd = 10 units(−3, 2)(5, 8)
From (−3, 2) to (5, 8): legs 8 across and 6 up.
d² = 8² + 6² = 64 + 36 = 100
d
=
√
100
=
10
units
This is an example. Type your own values to start a new problem.
d
=
(
−
(
)
)²
+
(
−
)²

Formulas

d
=
√(
(
x₂
−
x₁
)
2
+
(
y₂
−
y₁
)
2
)
10
=
√((5
−
(−3))²
+
(8 − 2)
2
)

Assumptions

•
The segment AB is the hypotenuse of a right triangle whose legs go straight across and straight up.
•
The legs are x₂ − x₁ and y₂ − y₁, so d = √((x₂ − x₁)² + (y₂ − y₁)²).
•
Squaring makes a negative change positive: the order of the points doesn’t matter.

Step-by-step

WE KNOW
x₁ = −3, y₁ = 2, x₂ = 5, y₂ = 8
FIND
distance AB (d)
Step 1 · Find distance AB (d)
Use d = √((x₂ − x₁)² + (y₂ − y₁)²)
The distance formula: the change across and the change up are the legs of a right triangle.
d
=
√((5
−
(−3))²
+
(8 − 2)
2
)
d
=
√
8
2
+
6
2
d
=
√
64 + 36
d
=
√
100
d
=
10
Check
Put the numbers back in. Both sides should match.
10
=
√((5
−
(−3))²
+
(8 − 2)
2
)
✓
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