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Grade 7 Math · Problem type

A circle in a square

Use this for “A circle of radius 5 is inside a square. What area is left in the corners?”

Diagram

r = 5 cmA = 25π cm²
s = 10 cm (side of the square)
Q = 100 cm² (area of the square)
L = 21.4602 cm² (area left in the corners)
This is an example. Type your own values to start a new problem.
r
Radius
example
s
Side of the square
calculated
Q
Area of the square
worked out (not typed)
A
Area of the circle
worked out (not typed)
L
Area left in the corners
worked out (not typed)

Formulas

s
=
2
×
r
(side
of
the
square
=
2
×
radius)
10 = 2 × 5
Q
=
s
2
(area
of
the
square
=
side
of
the
square²)
100
=
10
2
A
=
π
×
r
2
(area
of
the
circle
=
π
×
radius²)
25π
=
π
×
5
2
L
=
Q
−
A
(area
left
in
the
corners
=
area
of
the
square
−
area
of
the
circle)
21.4602 = 100 − 25π

Assumptions

•
The circle touches all four sides, so the square’s side is the diameter: 2r.
•
The area left in the corners is the square’s area minus the circle’s.
•
The corners are always about 21% of the square, whatever its size.

Step-by-step

WE KNOW
r = 5 cm (radius)
FIND
side of the square (s), area of the square (Q), area of the circle (A), area left in the corners (L)
Step 1 · Find side of the square (s)
Use s = 2 × r (side of the square = 2 × radius)
The circle touches both sides: the side is a diameter.
s
=
2
×
5
s
=
10
cm
Step 2 · Find area of the square (Q)
Use Q = s² (area of the square = side of the square²)
A
square’
s
area
is
its
side
times
itself.
Q
=
10
2
Q
=
100
cm²
Step 3 · Find area of the circle (A)
Use A = π × r² (area of the circle = π × radius²)
Square the radius, then multiply by π.
A
=
π
×
5
2
A
=
25
×
π
A
=
25π
cm²
(≈
78.54
cm²)
Step 4 · Find area left in the corners (L)
Use L = Q − A (area left in the corners = area of the square − area of the circle)
Take
the
circle’
s
area
from
the
square’
s
.
L
=
100
−
25π
L
≈
21.4602
cm²
Check
Put the numbers back in. Both sides should match.
10 = 2 × 5 ✓
100
=
10
2
✓
25π
=
π
×
5
2
✓
21.4602 ≈ 100 − 25π ✓
Topic check
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