SME
Grade 10 Science · Problem type
Percent yield
Use this for the percent yield from the actual and theoretical masses of product.
Diagram
79.9% of 34.06 g is 27.2 g.
This is an example. Type your own values to start a new problem.
p
%
=
y (g)
t (g)
×
100
Formulas
p
=
y
t
×
100
79.9 = 27.2/34.06 × 100
Assumptions
•
The theoretical yield is what the stoichiometry says the reactants can make.
•
The actual yield is what was weighed; spills and side reactions make it smaller.
Step-by-step
WE KNOW
t = 34.06 g, y = 27.2 g
FIND
percent yield (p)
Step 1 · Find percent yield (p)
Use p = y/t × 100
What you got as a percent of what you could have got.
p
=
27.2/34.06
×
100
p
=
0.7986
×
100
p
=
79.9%
Check
Put the numbers back in. Both sides should match.
79.9 ≈ 27.2/34.06 × 100 ✓
Topic check
See what you know: 5 questions on this topic
New questions each time. Pass to mark it complete.